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Jackpot
We attempted to create the most equitable jackpot that will be open source and will also save you a lot of time; do you want to have some fun? Get it right away because one ticket is one purchase of WLT tokens worth $100 or more
Our bot employs a simple mathematical method to calculate the amount of the current jackpot and the amount of the next jackpot
Everything at the jackpot address is drawn as follows:
The current jackpot is 50% of the total jackpot balance
Next jackpot: 25% of the jackpot balance
If the wallet contains 1 ETH in the jackpot
Current Jackpot: 0.5 ETH
Next Jackpot: 0.25 ETH
Amount | Chance |
|---|---|
$100 | 1% |
$200 | 2% |
$300 | 3% |
$400 | 4% |
$500 | 5% |
$600 | 6% |
$700 | 7% |
$800 | 8% |
$900 | 9% |
$1,000 | 10% |
Because the maximum chance of winning the jackpot is 10%, everything purchased from $1,000 will count as 10%
Assume you purchased $400 worth of WLT tokens, and the bot (you can follow the bot's announcement in our telegram channel) will generate your ticket at random: [8, 97, 22, 47]
In addition, the bot will generate a number from 1 to 100 at random to announce whether you won or not
You certainly can
def play(rounded_number): global amount0In global amount1Out global sender jack = balanceJpWallet() / 2 player_counts = {100: 1, 200: 2, 300: 3, 400: 4, 500: 5, 600: 6, 700: 7, 800: 8, 900: 9, 1000: 10} player_count = player_counts.get(rounded_number, 0) if player_count == 0: return "Invalid purchase value" player_numbers = [playerNumber() for _ in range(player_count)] bot_number = lottoNumber() print(player_numbers) print([bot_number]) print("amount0In:", amount0In) print("amount1Out:", amount1Out) print("sender:", sender)def playerNumber(): numbp = random.randint(1, 100) return numbpdef lottoNumber(): botNum = random.randint(1, 100) return botNumLast modified 7mo ago